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6t^2-11t-2=0
a = 6; b = -11; c = -2;
Δ = b2-4ac
Δ = -112-4·6·(-2)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-13}{2*6}=\frac{-2}{12} =-1/6 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+13}{2*6}=\frac{24}{12} =2 $
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